Geometrie-Viereck-Gleichschenkliges Trapez

$A = \frac{a+c}{ 2}\cdot h$
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$a = \frac{2\cdot A}{ h} - c$
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$c = \frac{2\cdot A}{ h} - a$
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$h = \frac{2\cdot A}{a+c}$
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Beispiel Nr: 05
$\begin{array}{l} \text{Gegeben:}\\\text{Grundlinie c} \qquad c \qquad [m] \\ \text{Höhe} \qquad h \qquad [m] \\ \text{Fläche} \qquad A \qquad [m^{2}] \\ \\ \text{Gesucht:} \\\text{Grundlinie a} \qquad a \qquad [m] \\ \\ a = \frac{2\cdot A}{ h} - c\\ \textbf{Gegeben:} \\ c=4m \qquad h=4m \qquad A=46m^{2} \qquad \\ \\ \textbf{Rechnung:} \\ a = \frac{2\cdot A}{ h} - c \\ c=4m\\ h=4m\\ A=46m^{2}\\ a = \frac{2\cdot 46m^{2}}{ 4m} - 4m\\\\a=19m \\\\\\ \small \begin{array}{|l|} \hline c=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline h=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 46 m^2 \\ \hline 4,6\cdot 10^{3} dm^2 \\ \hline 4,6\cdot 10^{5} cm^2 \\ \hline 4,6\cdot 10^{7} mm^2 \\ \hline \frac{23}{50} a \\ \hline 0,0046 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 19 m \\ \hline 190 dm \\ \hline 1,9\cdot 10^{3} cm \\ \hline 1,9\cdot 10^{4} mm \\ \hline 1,9\cdot 10^{7} \mu m \\ \hline \end{array} \end{array}$