Beispiel Nr: 02
$ \text{Gegeben:}\\\text{Körperhöhe} \qquad h \qquad [m] \\ \text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Radius 2} \qquad r_{2} \qquad [m] \\ \text{Radius 1} \qquad r_{1} \qquad [m] \\ \\ \text{Gesucht:} \\\text{Volumen} \qquad V \qquad [m^{3}] \\ \\ V = (r_{1} ^{2} - r_{2} ^{2} )\cdot \pi \cdot h\\ \textbf{Gegeben:} \\ h=4m \qquad \pi=3,14 \qquad r_{2}=3m \qquad r_{1}=5m \qquad \\ \\ \textbf{Rechnung:} \\ V = (r_{1} ^{2} - r_{2} ^{2} )\cdot \pi \cdot h \\ h=4m\\ \pi=3,14\\ r_{2}=3m\\ r_{1}=5m\\ V = (5m ^{2} - 3m ^{2} )\cdot 3,14 \cdot 4m\\\\V=201m^{3} \\ \small \begin{array}{|l|} \hline h=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline 0,004 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline r2=\\ \hline 3 m \\ \hline 30 dm \\ \hline 300 cm \\ \hline 3\cdot 10^{3} mm \\ \hline 3\cdot 10^{6} \mu m \\ \hline 0,003 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline r1=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline 0,005 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline V=\\ \hline 201 m^3 \\ \hline 2,01\cdot 10^{5} dm^3 \\ \hline 2,01\cdot 10^{8} cm^3 \\ \hline 2,01\cdot 10^{11} mm^3 \\ \hline 2,01\cdot 10^{5} l \\ \hline 2,01\cdot 10^{3} hl \\ \hline 2,01\cdot 10^{8} ml \\ \hline \end{array}\\$