Beispiel Nr: 01
$ \text{Gegeben:}\\\text{Winkel} \qquad \alpha \qquad [^{\circ}] \\ \text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Radius} \qquad r \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{r^{2} \cdot \pi \cdot \alpha }{ 360}\\ \textbf{Gegeben:} \\ \alpha=34^{\circ} \qquad \pi=3,14 \qquad r=52m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{r^{2} \cdot \pi \cdot \alpha }{ 360} \\ \alpha=34^{\circ}\\ \pi=3,14\\ r=52m\\ A = \frac{(52m)^{2} \cdot 3,14 \cdot 34^{\circ} }{ 360}\\\\A=802m^{2} \\\\\\ \tiny \begin{array}{|l|} \hline alpha=\\ \hline 34 ° \\ \hline 2,04\cdot 10^{3} \text{'} \\ \hline 1,22\cdot 10^{5} \text{''} \\ \hline 37,8 gon \\ \hline 0,593 rad \\ \hline 0,000593 mrad \\ \hline \end{array} \tiny \begin{array}{|l|} \hline r=\\ \hline 52 m \\ \hline 520 dm \\ \hline 5,2\cdot 10^{3} cm \\ \hline 5,2\cdot 10^{4} mm \\ \hline 5,2\cdot 10^{7} \mu m \\ \hline 0,052 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline A=\\ \hline 802 m^2 \\ \hline 8,02\cdot 10^{4} dm^2 \\ \hline 8,02\cdot 10^{6} cm^2 \\ \hline 8,02\cdot 10^{8} mm^2 \\ \hline 8,02 a \\ \hline 0,0802 ha \\ \hline 0,000802 km^2 \\ \hline \end{array}$