Beispiel Nr: 06
$ \text{Gegeben:}\\\text{Fläche} \qquad A \qquad [m^{2}] \\ \text{Grundlinie} \qquad g \qquad [m] \\ \\ \text{Gesucht:} \\\text{Höhe} \qquad h \qquad [m] \\ \\ h = \frac{A}{g}\\ \textbf{Gegeben:} \\ A=120m^{2} \qquad g=80m \qquad \\ \\ \textbf{Rechnung:} \\ h = \frac{A}{g} \\ A=120m^{2}\\ g=80m\\ h = \frac{120m^{2}}{80m}\\\\h=1\frac{1}{2}m \\ \small \begin{array}{|l|} \hline A=\\ \hline 120 m^2 \\ \hline 1,2\cdot 10^{4} dm^2 \\ \hline 1,2\cdot 10^{6} cm^2 \\ \hline 1,2\cdot 10^{8} mm^2 \\ \hline 1,2 a \\ \hline 0,012 ha \\ \hline 0,00012 km^2 \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline g=\\ \hline 80 m \\ \hline 800 dm \\ \hline 8\cdot 10^{3} cm \\ \hline 8\cdot 10^{4} mm \\ \hline 8\cdot 10^{7} \mu m \\ \hline 0,08 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline h=\\ \hline 1,5 m \\ \hline 15 dm \\ \hline 150 cm \\ \hline 1,5\cdot 10^{3} mm \\ \hline 1,5\cdot 10^{6} \mu m \\ \hline 0,0015 km \\ \hline \end{array}\\$