Beispiel Nr: 02
$\text{Gegeben:}\\\text{Höhe} \qquad c \qquad [m] \\ \text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Oberfläche} \qquad O \qquad [m^{2}] \\ \\ O = 2\cdot (a\cdot b + a\cdot c + b\cdot c)\\ \textbf{Gegeben:} \\ c=2m \qquad b=1m \qquad a=9m \qquad \\ \\ \textbf{Rechnung:} \\ O = 2\cdot (a\cdot b + a\cdot c + b\cdot c) \\ c=2m\\ b=1m\\ a=9m\\ O = 2\cdot (9m\cdot 1m + 9m \cdot 2m + 1m\cdot 2m)\\\\O=58m^{2} \\\\\\ \tiny \begin{array}{|l|} \hline c=\\ \hline 2 m \\ \hline 20 dm \\ \hline 200 cm \\ \hline 2\cdot 10^{3} mm \\ \hline 2\cdot 10^{6} \mu m \\ \hline 0,002 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline b=\\ \hline 1 m \\ \hline 10 dm \\ \hline 100 cm \\ \hline 10^{3} mm \\ \hline 10^{6} \mu m \\ \hline 0,001 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline a=\\ \hline 9 m \\ \hline 90 dm \\ \hline 900 cm \\ \hline 9\cdot 10^{3} mm \\ \hline 9\cdot 10^{6} \mu m \\ \hline 0,009 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline O=\\ \hline 58 m^2 \\ \hline 5,8\cdot 10^{3} dm^2 \\ \hline 5,8\cdot 10^{5} cm^2 \\ \hline 5,8\cdot 10^{7} mm^2 \\ \hline 0,58 a \\ \hline 0,0058 ha \\ \hline 5,8\cdot 10^{-5} km^2 \\ \hline \end{array}$