Beispiel Nr: 02
$ \text{Gegeben:}\\\text{Länge} \qquad b \qquad [m] \\ \text{Diagonale} \qquad d \qquad [m] \\ \\ \text{Gesucht:} \\\text{Breite} \qquad a \qquad [m] \\ \\ a = \sqrt{d^{2} -b^{2} }\\ \textbf{Gegeben:} \\ d=10m \qquad b=6m \qquad \\ \\ \textbf{Rechnung:} \\ a = \sqrt{d^{2} -b^{2} } \\ b=6m\\ d=10m\\ a = \sqrt{(10m)^{2} -(6m)^{2} }\\\\a=8m \\ \small \begin{array}{|l|} \hline d=\\ \hline 10 m \\ \hline 100 dm \\ \hline 10^{3} cm \\ \hline 10^{4} mm \\ \hline 10^{7} \mu m \\ \hline 0,01 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline b=\\ \hline 6 m \\ \hline 60 dm \\ \hline 600 cm \\ \hline 6\cdot 10^{3} mm \\ \hline 6\cdot 10^{6} \mu m \\ \hline 0,006 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline a=\\ \hline 8 m \\ \hline 80 dm \\ \hline 800 cm \\ \hline 8\cdot 10^{3} mm \\ \hline 8\cdot 10^{6} \mu m \\ \hline 0,008 km \\ \hline \end{array}\\$