Beispiel Nr: 05
$ \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Diagonale} \qquad d \qquad [m] \\ \\ d = \sqrt{a^{2} +b^{2} }\\ \textbf{Gegeben:} \\ b=12m \qquad a=16m \qquad \\ \\ \textbf{Rechnung:} \\ d = \sqrt{a^{2} +b^{2} } \\ b=12m\\ a=16m\\ d = \sqrt{(16m)^{2} +(12m)^{2} }\\\\d=20m \\\\\\ \tiny \begin{array}{|l|} \hline b=\\ \hline 12 m \\ \hline 120 dm \\ \hline 1,2\cdot 10^{3} cm \\ \hline 1,2\cdot 10^{4} mm \\ \hline 1,2\cdot 10^{7} \mu m \\ \hline 0,012 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline a=\\ \hline 16 m \\ \hline 160 dm \\ \hline 1,6\cdot 10^{3} cm \\ \hline 1,6\cdot 10^{4} mm \\ \hline 1,6\cdot 10^{7} \mu m \\ \hline 0,016 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline d=\\ \hline 20 m \\ \hline 200 dm \\ \hline 2\cdot 10^{3} cm \\ \hline 2\cdot 10^{4} mm \\ \hline 2\cdot 10^{7} \mu m \\ \hline 0,02 km \\ \hline \end{array}$