Beispiel Nr: 10
$ \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Diagonale} \qquad d \qquad [m] \\ \\ d = \sqrt{a^{2} +b^{2} }\\ \textbf{Gegeben:} \\ b=\frac{1}{50}m \qquad a=\frac{2}{5}m \qquad \\ \\ \textbf{Rechnung:} \\ d = \sqrt{a^{2} +b^{2} } \\ b=\frac{1}{50}m\\ a=\frac{2}{5}m\\ d = \sqrt{(\frac{2}{5}m)^{2} +(\frac{1}{50}m)^{2} }\\\\d=0,4m \\ \small \begin{array}{|l|} \hline b=\\ \hline 0,02 m \\ \hline 0,2 dm \\ \hline 2 cm \\ \hline 20 mm \\ \hline 2\cdot 10^{4} \mu m \\ \hline 2\cdot 10^{-5} km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline a=\\ \hline 0,4 m \\ \hline 4 dm \\ \hline 40 cm \\ \hline 400 mm \\ \hline 4\cdot 10^{5} \mu m \\ \hline 0,0004 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline d=\\ \hline 0,4 m \\ \hline 4 dm \\ \hline 40 cm \\ \hline 400 mm \\ \hline 4\cdot 10^{5} \mu m \\ \hline 0,0004 km \\ \hline \end{array}\\$