Beispiel Nr: 06
$ \text{Gegeben:}\\\text{Ankathete zu } \alpha \qquad b \qquad [m] \\ \text{Gegenkathete zu } \alpha \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Winkel} \qquad \alpha \qquad [^{\circ}] \\ \\ tan \alpha = \frac{a}{b}\\ \textbf{Gegeben:} \\ b=6\frac{1}{5}m \qquad a=3\frac{4}{5}m \qquad \\ \\ \textbf{Rechnung:} \\ tan \alpha = \frac{a}{b} \\ b=6\frac{1}{5}m\\ a=3\frac{4}{5}m\\ tan \alpha = \frac{3\frac{4}{5}m}{6\frac{1}{5}m}\\\\\alpha=31,5^{\circ} \\ \small \begin{array}{|l|} \hline b=\\ \hline 6,2 m \\ \hline 62 dm \\ \hline 620 cm \\ \hline 6,2\cdot 10^{3} mm \\ \hline 6,2\cdot 10^{6} \mu m \\ \hline 0,0062 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline a=\\ \hline 3,8 m \\ \hline 38 dm \\ \hline 380 cm \\ \hline 3,8\cdot 10^{3} mm \\ \hline 3,8\cdot 10^{6} \mu m \\ \hline 0,0038 km \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline alpha=\\ \hline 31,5 ° \\ \hline 1,89\cdot 10^{3} \text{'} \\ \hline 1,13\cdot 10^{5} \text{''} \\ \hline 35 gon \\ \hline 0,55 rad \\ \hline 0,00055 mrad \\ \hline \end{array}\\$