Beispiel Nr: 07
$ \text{Gegeben:}\\\text{Winkel} \qquad \alpha \qquad [^{\circ}] \\ \text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Radius} \qquad r \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{r^{2} \cdot \pi \cdot \alpha }{ 360}\\ \textbf{Gegeben:} \\ \alpha=40^{\circ} \qquad \pi=3,14 \qquad r=5m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{r^{2} \cdot \pi \cdot \alpha }{ 360} \\ \alpha=40^{\circ}\\ \pi=3,14\\ r=5m\\ A = \frac{(5m)^{2} \cdot 3,14 \cdot 40^{\circ} }{ 360}\\\\A=8,73m^{2} \\\\\\ \tiny \begin{array}{|l|} \hline alpha=\\ \hline 40 ° \\ \hline 2,4\cdot 10^{3} \text{'} \\ \hline 1,44\cdot 10^{5} \text{''} \\ \hline 44,4 gon \\ \hline 0,698 rad \\ \hline 0,000698 mrad \\ \hline \end{array} \tiny \begin{array}{|l|} \hline r=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline 0,005 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline A=\\ \hline 8,73 m^2 \\ \hline 873 dm^2 \\ \hline 8,73\cdot 10^{4} cm^2 \\ \hline 8,73\cdot 10^{6} mm^2 \\ \hline 0,0873 a \\ \hline 0,000873 ha \\ \hline 8,73\cdot 10^{-6} km^2 \\ \hline \end{array}$