Beispiel Nr: 03
$ \text{Gegeben:}\\\text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Fläche} \qquad A \qquad [m^{2}] \\ \text{Winkel} \qquad \alpha \qquad [^{\circ}] \\ \\ \text{Gesucht:} \\\text{Radius} \qquad r \qquad [m] \\ \\ r = \sqrt{\frac{A\cdot 360}{\alpha \cdot \pi }}\\ \textbf{Gegeben:} \\ \pi=3,14 \qquad A=15m^{2} \qquad \alpha=90^{\circ} \qquad \\ \\ \textbf{Rechnung:} \\ r = \sqrt{\frac{A\cdot 360}{\alpha \cdot \pi }} \\ \pi=3,14\\ A=15m^{2}\\ \alpha=90^{\circ}\\ r = \sqrt{\frac{15m^{2}\cdot 360}{90^{\circ} \cdot 3,14 }}\\\\r=4,37m \\\\ \tiny \begin{array}{|l|} \hline A=\\ \hline 15 m^2 \\ \hline 1,5\cdot 10^{3} dm^2 \\ \hline 1,5\cdot 10^{5} cm^2 \\ \hline 1,5\cdot 10^{7} mm^2 \\ \hline 0,15 a \\ \hline 0,0015 ha \\ \hline 1,5\cdot 10^{-5} km^2 \\ \hline \end{array} \tiny \begin{array}{|l|} \hline alpha=\\ \hline 90 ° \\ \hline 5,4\cdot 10^{3} \text{'} \\ \hline 3,24\cdot 10^{5} \text{''} \\ \hline 100 gon \\ \hline 1,57 rad \\ \hline 0,00157 mrad \\ \hline \end{array} \tiny \begin{array}{|l|} \hline r=\\ \hline 4,37 m \\ \hline 43,7 dm \\ \hline 437 cm \\ \hline 4,37\cdot 10^{3} mm \\ \hline 4,37\cdot 10^{6} \mu m \\ \hline 0,00437 km \\ \hline \end{array}$