Geometrie-Dreieck-Gleichschenkliges rechtwinkliges Dreieck


  • $A = \frac{a\cdot b}{ 2}$
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    $a = \frac{A \cdot 2}{ b}$
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    $b = \frac{A \cdot 2}{ a}$
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    $a^{2} + b^{2}=c^{2}$
    $c =\sqrt{a^{2} + b^{2} }$
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    $a =\sqrt{c^{2} - b^{2} }$
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    $b =\sqrt{c^{2} - a^{2} }$
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    $h^{2} = p\cdot q$
    $h = \sqrt{p\cdot q}$
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    $q = \frac{h^{2} }{p}$
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    $p = \frac{h^{2} }{q}$
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    $a^{2} = c\cdot p \qquad b^{2} = c\cdot q $
    $a = \sqrt{c\cdot p}$
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    $c = \frac{a^{2} }{p}$
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    $p = \frac{a^{2} }{c}$
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Beispiel Nr: 04
$ \text{Gegeben:}\\\text{Hypotenusenabschnitt} \qquad p \qquad [m] \\ \text{Gegenkathete zu } \alpha \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Hypotenuse} \qquad c \qquad [m] \\ \\ c = \frac{a^{2} }{p}\\ \textbf{Gegeben:} \\ p=4m \qquad a=5m \qquad \\ \\ \textbf{Rechnung:} \\ c = \frac{a^{2} }{p} \\ p=4m\\ a=5m\\ c = \frac{(5m)^{2} }{4m}\\\\c=6\frac{1}{4}m \\\\\\ \small \begin{array}{|l|} \hline p=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline c=\\ \hline 6\frac{1}{4} m \\ \hline 62\frac{1}{2} dm \\ \hline 625 cm \\ \hline 6,25\cdot 10^{3} mm \\ \hline 6,25\cdot 10^{6} \mu m \\ \hline \end{array}$