Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 02
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-\frac{1}{2}x^2+4\frac{1}{2} =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l|l}
\begin{array}{l}
\text{Umformen}\\ \hline
-\frac{1}{2}x^2+4\frac{1}{2} =0 \qquad /-4\frac{1}{2} \\
-\frac{1}{2}x^2= -4\frac{1}{2} \qquad /:\left(-\frac{1}{2}\right) \\
x^2=\displaystyle\frac{-4\frac{1}{2}}{-\frac{1}{2}} \\
x=\pm\sqrt{9} \\
x_1=3 \qquad x_2=-3
\end{array}&
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-\frac{1}{2}x^{2}+0x+4\frac{1}{2} =0
\\
x_{1/2}=\displaystyle\frac{-0 \pm\sqrt{0^{2}-4\cdot \left(-\frac{1}{2}\right) \cdot 4\frac{1}{2}}}{2\cdot\left(-\frac{1}{2}\right)}
\\
x_{1/2}=\displaystyle \frac{-0 \pm\sqrt{9}}{-1}
\\
x_{1/2}=\displaystyle \frac{0 \pm3}{-1}
\\
x_{1}=\displaystyle \frac{0 +3}{-1} \qquad x_{2}=\displaystyle \frac{0 -3}{-1}
\\
x_{1}=-3 \qquad x_{2}=3
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-\frac{1}{2}x^{2}+0x+4\frac{1}{2} =0 \qquad /:-\frac{1}{2}
\\
x^{2}+0x-9 =0
\\
x_{1/2}=\displaystyle -\frac{0}{2}\pm\sqrt{\left(\frac{0}{2}\right)^2- \left(-9\right)}
\\
x_{1/2}=\displaystyle 0\pm\sqrt{9}
\\
x_{1/2}=\displaystyle 0\pm3
\\
x_{1}=3 \qquad x_{2}=-3
\end{array}\\ \end{array} \end{array}$