Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 04
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
\frac{1}{4}x^2-2 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l|l}
\begin{array}{l}
\text{Umformen}\\ \hline
\frac{1}{4}x^2-2 =0 \qquad /+2 \\
\frac{1}{4}x^2= 2 \qquad /:\frac{1}{4} \\
x^2=\displaystyle\frac{2}{\frac{1}{4}} \\
x=\pm\sqrt{8} \\
x_1=2,83 \qquad x_2=-2,83
\end{array}&
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
\frac{1}{4}x^{2}+0x-2 =0
\\
x_{1/2}=\displaystyle\frac{-0 \pm\sqrt{0^{2}-4\cdot \frac{1}{4} \cdot \left(-2\right)}}{2\cdot\frac{1}{4}}
\\
x_{1/2}=\displaystyle \frac{-0 \pm\sqrt{2}}{\frac{1}{2}}
\\
x_{1/2}=\displaystyle \frac{0 \pm1,41}{\frac{1}{2}}
\\
x_{1}=\displaystyle \frac{0 +1,41}{\frac{1}{2}} \qquad x_{2}=\displaystyle \frac{0 -1,41}{\frac{1}{2}}
\\
x_{1}=2,83 \qquad x_{2}=-2,83
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
\frac{1}{4}x^{2}+0x-2 =0 \qquad /:\frac{1}{4}
\\
x^{2}+0x-8 =0
\\
x_{1/2}=\displaystyle -\frac{0}{2}\pm\sqrt{\left(\frac{0}{2}\right)^2- \left(-8\right)}
\\
x_{1/2}=\displaystyle 0\pm\sqrt{8}
\\
x_{1/2}=\displaystyle 0\pm2,83
\\
x_{1}=2,83 \qquad x_{2}=-2,83
\end{array}\\ \end{array} \end{array}$