Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 05
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
\frac{1}{4}x^2-3 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l|l}
\begin{array}{l}
\text{Umformen}\\ \hline
\frac{1}{4}x^2-3 =0 \qquad /+3 \\
\frac{1}{4}x^2= 3 \qquad /:\frac{1}{4} \\
x^2=\displaystyle\frac{3}{\frac{1}{4}} \\
x=\pm\sqrt{12} \\
x_1=3,46 \qquad x_2=-3,46
\end{array}&
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
\frac{1}{4}x^{2}+0x-3 =0
\\
x_{1/2}=\displaystyle\frac{-0 \pm\sqrt{0^{2}-4\cdot \frac{1}{4} \cdot \left(-3\right)}}{2\cdot\frac{1}{4}}
\\
x_{1/2}=\displaystyle \frac{-0 \pm\sqrt{3}}{\frac{1}{2}}
\\
x_{1/2}=\displaystyle \frac{0 \pm1,73}{\frac{1}{2}}
\\
x_{1}=\displaystyle \frac{0 +1,73}{\frac{1}{2}} \qquad x_{2}=\displaystyle \frac{0 -1,73}{\frac{1}{2}}
\\
x_{1}=3,46 \qquad x_{2}=-3,46
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
\frac{1}{4}x^{2}+0x-3 =0 \qquad /:\frac{1}{4}
\\
x^{2}+0x-12 =0
\\
x_{1/2}=\displaystyle -\frac{0}{2}\pm\sqrt{\left(\frac{0}{2}\right)^2- \left(-12\right)}
\\
x_{1/2}=\displaystyle 0\pm\sqrt{12}
\\
x_{1/2}=\displaystyle 0\pm3,46
\\
x_{1}=3,46 \qquad x_{2}=-3,46
\end{array}\\ \end{array} \end{array}$