Algebra-Grundlagen-Logarithmen

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Beispiel Nr: 07
c=logbabc=alogca+logcb=logc(ab)logcalogcb=logcablogcan=nlogcaGegeben:a=3b=4c=5n=6Rechnung:log43=0,79240,792=3log53+log54=log5(34)=log5(34)=1,54log53log54=log534=0,179log536=6log53=4,1log43=log53log54=0,792