Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 07
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
x^2-2 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l|l}
\begin{array}{l}
\text{Umformen}\\ \hline
1x^2-2 =0 \qquad /+2 \\
1x^2= 2 \qquad /:1 \\
x^2=\displaystyle\frac{2}{1} \\
x=\pm\sqrt{2} \\
x_1=1,41 \qquad x_2=-1,41
\end{array}&
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
1x^{2}+0x-2 =0
\\
x_{1/2}=\displaystyle\frac{-0 \pm\sqrt{0^{2}-4\cdot 1 \cdot \left(-2\right)}}{2\cdot1}
\\
x_{1/2}=\displaystyle \frac{-0 \pm\sqrt{8}}{2}
\\
x_{1/2}=\displaystyle \frac{0 \pm2,83}{2}
\\
x_{1}=\displaystyle \frac{0 +2,83}{2} \qquad x_{2}=\displaystyle \frac{0 -2,83}{2}
\\
x_{1}=1,41 \qquad x_{2}=-1,41
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
\\
x^{2}+0x-2 =0
\\
x_{1/2}=\displaystyle -\frac{0}{2}\pm\sqrt{\left(\frac{0}{2}\right)^2- \left(-2\right)}
\\
x_{1/2}=\displaystyle 0\pm\sqrt{2}
\\
x_{1/2}=\displaystyle 0\pm1,41
\\
x_{1}=1,41 \qquad x_{2}=-1,41
\end{array}\\ \end{array} \end{array}$