Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 14
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
x^2+3x-10 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
1x^{2}+3x-10 =0
\\
x_{1/2}=\displaystyle\frac{-3 \pm\sqrt{3^{2}-4\cdot 1 \cdot \left(-10\right)}}{2\cdot1}
\\
x_{1/2}=\displaystyle \frac{-3 \pm\sqrt{49}}{2}
\\
x_{1/2}=\displaystyle \frac{-3 \pm7}{2}
\\
x_{1}=\displaystyle \frac{-3 +7}{2} \qquad x_{2}=\displaystyle \frac{-3 -7}{2}
\\
x_{1}=2 \qquad x_{2}=-5
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
\\
x^{2}+3x-10 =0
\\
x_{1/2}=\displaystyle -\frac{3}{2}\pm\sqrt{\left(\frac{3}{2}\right)^2- \left(-10\right)}
\\
x_{1/2}=\displaystyle -1\frac{1}{2}\pm\sqrt{12\frac{1}{4}}
\\
x_{1/2}=\displaystyle -1\frac{1}{2}\pm3\frac{1}{2}
\\
x_{1}=2 \qquad x_{2}=-5
\end{array}\\ \end{array} \end{array}$