Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 16
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
x^2-8x-20 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
1x^{2}-8x-20 =0
\\
x_{1/2}=\displaystyle\frac{+8 \pm\sqrt{\left(-8\right)^{2}-4\cdot 1 \cdot \left(-20\right)}}{2\cdot1}
\\
x_{1/2}=\displaystyle \frac{+8 \pm\sqrt{144}}{2}
\\
x_{1/2}=\displaystyle \frac{8 \pm12}{2}
\\
x_{1}=\displaystyle \frac{8 +12}{2} \qquad x_{2}=\displaystyle \frac{8 -12}{2}
\\
x_{1}=10 \qquad x_{2}=-2
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
\\
x^{2}-8x-20 =0
\\
x_{1/2}=\displaystyle -\frac{-8}{2}\pm\sqrt{\left(\frac{\left(-8\right)}{2}\right)^2- \left(-20\right)}
\\
x_{1/2}=\displaystyle 4\pm\sqrt{36}
\\
x_{1/2}=\displaystyle 4\pm6
\\
x_{1}=10 \qquad x_{2}=-2
\end{array}\\ \end{array} \end{array}$