Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 18
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-\frac{1}{3}x^2-2x+3 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-\frac{1}{3}x^{2}-2x+3 =0
\\
x_{1/2}=\displaystyle\frac{+2 \pm\sqrt{\left(-2\right)^{2}-4\cdot \left(-\frac{1}{3}\right) \cdot 3}}{2\cdot\left(-\frac{1}{3}\right)}
\\
x_{1/2}=\displaystyle \frac{+2 \pm\sqrt{8}}{-\frac{2}{3}}
\\
x_{1/2}=\displaystyle \frac{2 \pm2,83}{-\frac{2}{3}}
\\
x_{1}=\displaystyle \frac{2 +2,83}{-\frac{2}{3}} \qquad x_{2}=\displaystyle \frac{2 -2,83}{-\frac{2}{3}}
\\
x_{1}=-7,24 \qquad x_{2}=1,24
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-\frac{1}{3}x^{2}-2x+3 =0 \qquad /:-\frac{1}{3}
\\
x^{2}+6x-9 =0
\\
x_{1/2}=\displaystyle -\frac{6}{2}\pm\sqrt{\left(\frac{6}{2}\right)^2- \left(-9\right)}
\\
x_{1/2}=\displaystyle -3\pm\sqrt{18}
\\
x_{1/2}=\displaystyle -3\pm4,24
\\
x_{1}=1,24 \qquad x_{2}=-7,24
\end{array}\\ \end{array} \end{array}$