Algebra-Lineares Gleichungssystem-Additionsverfahren (2)
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Beispiel Nr: 21
$\begin{array}{l}
\text{Gegeben:} \\
a1 \cdot x +b1 \cdot y =c1\\
a2 \cdot x +b2 \cdot y =c2 \\
\\ \text{Gesucht:} \\\text{x und y}
\\ \\ \textbf{Gegeben:} \\
\\
2 x -7 y =-8\\
7 x -1 y = -9 \\
\\
\\ \\ \textbf{Rechnung:} \\\begin{array}{l|l}
\begin{array}{l}
\\I \qquad 2 x -7 y =-8\\
II \qquad 7 x -1 y = -9 \\
I \qquad 2 x -7 y =-8 \qquad / \cdot7\\
II \qquad 7 x -1 y = -9 \qquad / \cdot\left(-2\right)\\
I \qquad 14 x -49 y =-56\\
II \qquad -14 x +2 y = 18 \\
\text{I + II}\\
I \qquad 14 x -14 x-49 y +2 y =-56 +18\\
-47 y = -38 \qquad /:\left(-47\right) \\
y = \frac{-38}{-47} \\
y=\frac{38}{47} \\
\text{y in I}\\
I \qquad 2 x -7\cdot \frac{38}{47} =-8 \\
2 x -5\frac{31}{47} =-8 \qquad / +5\frac{31}{47} \\
2 x =-8 +5\frac{31}{47} \\
2 x =-2\frac{16}{47} \qquad / :2 \\
x = \frac{-2\frac{16}{47}}{2} \\
x=-1\frac{8}{47} \\
L=\{-1\frac{8}{47}/\frac{38}{47}\}
\end{array} &
\begin{array}{l}
\\I \qquad 2 x -7 y =-8\\
II \qquad 7 x -1 y = -9 \\
I \qquad 2 x -7 y =-8 \qquad / \cdot\left(-1\right)\\
II \qquad 7 x -1 y = -9 \qquad / \cdot7\\
I \qquad -2 x +7 y =8\\
II \qquad 49 x -7 y = -63 \\
\text{I + II}\\
I \qquad -2 x +49 x+7 y -7 y =8 -63\\
47 x = -55 \qquad /:47 \\
x = \frac{-55}{47} \\
x=-1\frac{8}{47} \\
\text{x in I}\\
I \qquad 2 \cdot \left(-1\frac{8}{47}\right) -7y =-8 \\
-7 y -2\frac{16}{47} =-8 \qquad / +2\frac{16}{47} \\
-7 y =-8 +2\frac{16}{47} \\
-7 y =-5\frac{31}{47} \qquad / :\left(-7\right) \\
y = \frac{-5\frac{31}{47}}{-7} \\
y=\frac{38}{47} \\
L=\{-1\frac{8}{47}/\frac{38}{47}\} \end{array}
\end{array}
\end{array}$