Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 21
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
2x^2+4x =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l|l}
\begin{array}{l}
\text{x-Ausklammern}\\ \hline
2x^{2}+4x =0 \\
x(2x +4)=0 \\
\\ 2 x+4 =0 \qquad /-4 \\
2 x= -4 \qquad /:2 \\
x=\displaystyle\frac{-4}{2}\\
x_1=0\\
x_2=-2
\end{array}&
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
2x^{2}+4x+0 =0
\\
x_{1/2}=\displaystyle\frac{-4 \pm\sqrt{4^{2}-4\cdot 2 \cdot 0}}{2\cdot2}
\\
x_{1/2}=\displaystyle \frac{-4 \pm\sqrt{16}}{4}
\\
x_{1/2}=\displaystyle \frac{-4 \pm4}{4}
\\
x_{1}=\displaystyle \frac{-4 +4}{4} \qquad x_{2}=\displaystyle \frac{-4 -4}{4}
\\
x_{1}=0 \qquad x_{2}=-2
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
2x^{2}+4x+0 =0 \qquad /:2
\\
x^{2}+2x+0 =0
\\
x_{1/2}=\displaystyle -\frac{2}{2}\pm\sqrt{\left(\frac{2}{2}\right)^2- 0}
\\
x_{1/2}=\displaystyle -1\pm\sqrt{1}
\\
x_{1/2}=\displaystyle -1\pm1
\\
x_{1}=0 \qquad x_{2}=-2
\end{array}\\ \end{array} \end{array}$