Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 23
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-2x^2+3x+4 =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-2x^{2}+3x+4 =0
\\
x_{1/2}=\displaystyle\frac{-3 \pm\sqrt{3^{2}-4\cdot \left(-2\right) \cdot 4}}{2\cdot\left(-2\right)}
\\
x_{1/2}=\displaystyle \frac{-3 \pm\sqrt{41}}{-4}
\\
x_{1/2}=\displaystyle \frac{-3 \pm6,4}{-4}
\\
x_{1}=\displaystyle \frac{-3 +6,4}{-4} \qquad x_{2}=\displaystyle \frac{-3 -6,4}{-4}
\\
x_{1}=-0,851 \qquad x_{2}=2,35
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-2x^{2}+3x+4 =0 \qquad /:-2
\\
x^{2}-1\frac{1}{2}x-2 =0
\\
x_{1/2}=\displaystyle -\frac{-1\frac{1}{2}}{2}\pm\sqrt{\left(\frac{\left(-1\frac{1}{2}\right)}{2}\right)^2- \left(-2\right)}
\\
x_{1/2}=\displaystyle \frac{3}{4}\pm\sqrt{2\frac{9}{16}}
\\
x_{1/2}=\displaystyle \frac{3}{4}\pm1,6
\\
x_{1}=2,35 \qquad x_{2}=-0,851
\end{array}\\ \end{array} \end{array}$