Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 28
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-\frac{32}{81}x^2-\frac{32}{81}x+7\frac{73}{81} =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-\frac{32}{81}x^{2}-\frac{32}{81}x+7\frac{73}{81} =0
\\
x_{1/2}=\displaystyle\frac{+\frac{32}{81} \pm\sqrt{\left(-\frac{32}{81}\right)^{2}-4\cdot \left(-\frac{32}{81}\right) \cdot 7\frac{73}{81}}}{2\cdot\left(-\frac{32}{81}\right)}
\\
x_{1/2}=\displaystyle \frac{+\frac{32}{81} \pm\sqrt{12\frac{52}{81}}}{-\frac{64}{81}}
\\
x_{1/2}=\displaystyle \frac{\frac{32}{81} \pm3\frac{5}{9}}{-\frac{64}{81}}
\\
x_{1}=\displaystyle \frac{\frac{32}{81} +3\frac{5}{9}}{-\frac{64}{81}} \qquad x_{2}=\displaystyle \frac{\frac{32}{81} -3\frac{5}{9}}{-\frac{64}{81}}
\\
x_{1}=-5 \qquad x_{2}=4
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-\frac{32}{81}x^{2}-\frac{32}{81}x+7\frac{73}{81} =0 \qquad /:-\frac{32}{81}
\\
x^{2}+1x-20 =0
\\
x_{1/2}=\displaystyle -\frac{1}{2}\pm\sqrt{\left(\frac{1}{2}\right)^2- \left(-20\right)}
\\
x_{1/2}=\displaystyle -\frac{1}{2}\pm\sqrt{20\frac{1}{4}}
\\
x_{1/2}=\displaystyle -\frac{1}{2}\pm4\frac{1}{2}
\\
x_{1}=4 \qquad x_{2}=-5
\end{array}\\ \end{array} \end{array}$