Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 35
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-\frac{1}{8}x^2+\frac{1}{4}x+7\frac{7}{8} =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-\frac{1}{8}x^{2}+\frac{1}{4}x+7\frac{7}{8} =0
\\
x_{1/2}=\displaystyle\frac{-\frac{1}{4} \pm\sqrt{\left(\frac{1}{4}\right)^{2}-4\cdot \left(-\frac{1}{8}\right) \cdot 7\frac{7}{8}}}{2\cdot\left(-\frac{1}{8}\right)}
\\
x_{1/2}=\displaystyle \frac{-\frac{1}{4} \pm\sqrt{4}}{-\frac{1}{4}}
\\
x_{1/2}=\displaystyle \frac{-\frac{1}{4} \pm2}{-\frac{1}{4}}
\\
x_{1}=\displaystyle \frac{-\frac{1}{4} +2}{-\frac{1}{4}} \qquad x_{2}=\displaystyle \frac{-\frac{1}{4} -2}{-\frac{1}{4}}
\\
x_{1}=-7 \qquad x_{2}=9
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-\frac{1}{8}x^{2}+\frac{1}{4}x+7\frac{7}{8} =0 \qquad /:-\frac{1}{8}
\\
x^{2}-2x-63 =0
\\
x_{1/2}=\displaystyle -\frac{-2}{2}\pm\sqrt{\left(\frac{\left(-2\right)}{2}\right)^2- \left(-63\right)}
\\
x_{1/2}=\displaystyle 1\pm\sqrt{64}
\\
x_{1/2}=\displaystyle 1\pm8
\\
x_{1}=9 \qquad x_{2}=-7
\end{array}\\ \end{array} \end{array}$