Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 38
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-2\frac{2}{9}x^2-2\frac{2}{9}x+4\frac{4}{9} =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-2\frac{2}{9}x^{2}-2\frac{2}{9}x+4\frac{4}{9} =0
\\
x_{1/2}=\displaystyle\frac{+2\frac{2}{9} \pm\sqrt{\left(-2\frac{2}{9}\right)^{2}-4\cdot \left(-2\frac{2}{9}\right) \cdot 4\frac{4}{9}}}{2\cdot\left(-2\frac{2}{9}\right)}
\\
x_{1/2}=\displaystyle \frac{+2\frac{2}{9} \pm\sqrt{44\frac{4}{9}}}{-4\frac{4}{9}}
\\
x_{1/2}=\displaystyle \frac{2\frac{2}{9} \pm6\frac{2}{3}}{-4\frac{4}{9}}
\\
x_{1}=\displaystyle \frac{2\frac{2}{9} +6\frac{2}{3}}{-4\frac{4}{9}} \qquad x_{2}=\displaystyle \frac{2\frac{2}{9} -6\frac{2}{3}}{-4\frac{4}{9}}
\\
x_{1}=-2 \qquad x_{2}=1
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-2\frac{2}{9}x^{2}-2\frac{2}{9}x+4\frac{4}{9} =0 \qquad /:-2\frac{2}{9}
\\
x^{2}+1x-2 =0
\\
x_{1/2}=\displaystyle -\frac{1}{2}\pm\sqrt{\left(\frac{1}{2}\right)^2- \left(-2\right)}
\\
x_{1/2}=\displaystyle -\frac{1}{2}\pm\sqrt{2\frac{1}{4}}
\\
x_{1/2}=\displaystyle -\frac{1}{2}\pm1\frac{1}{2}
\\
x_{1}=1 \qquad x_{2}=-2
\end{array}\\ \end{array} \end{array}$