Algebra-Gleichungen-Quadratische Gleichung
$ ax^{2}+bx+c=0 $
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Beispiel Nr: 44
$\begin{array}{l} \text{Gegeben:} ax^{2}+bx+c=0
\\ \text{Gesucht:} \\ \text{Lösung der Gleichung} \\
\\ ax^{2}+bx+c=0 \\ \textbf{Gegeben:} \\
-\frac{24}{49}x^2+2\frac{22}{49}x+2\frac{46}{49} =0
\\ \\ \textbf{Rechnung:} \\
\begin{array}{l|l|l}
\begin{array}{l}
\text{a-b-c Formel}\\ \hline
\\
-\frac{24}{49}x^{2}+2\frac{22}{49}x+2\frac{46}{49} =0
\\
x_{1/2}=\displaystyle\frac{-2\frac{22}{49} \pm\sqrt{\left(2\frac{22}{49}\right)^{2}-4\cdot \left(-\frac{24}{49}\right) \cdot 2\frac{46}{49}}}{2\cdot\left(-\frac{24}{49}\right)}
\\
x_{1/2}=\displaystyle \frac{-2\frac{22}{49} \pm\sqrt{11\frac{37}{49}}}{-\frac{48}{49}}
\\
x_{1/2}=\displaystyle \frac{-2\frac{22}{49} \pm3\frac{3}{7}}{-\frac{48}{49}}
\\
x_{1}=\displaystyle \frac{-2\frac{22}{49} +3\frac{3}{7}}{-\frac{48}{49}} \qquad x_{2}=\displaystyle \frac{-2\frac{22}{49} -3\frac{3}{7}}{-\frac{48}{49}}
\\
x_{1}=-1 \qquad x_{2}=6
\end{array}&
\begin{array}{l}
\text{p-q Formel}\\ \hline
\\
-\frac{24}{49}x^{2}+2\frac{22}{49}x+2\frac{46}{49} =0 \qquad /:-\frac{24}{49}
\\
x^{2}-5x-6 =0
\\
x_{1/2}=\displaystyle -\frac{-5}{2}\pm\sqrt{\left(\frac{\left(-5\right)}{2}\right)^2- \left(-6\right)}
\\
x_{1/2}=\displaystyle 2\frac{1}{2}\pm\sqrt{12\frac{1}{4}}
\\
x_{1/2}=\displaystyle 2\frac{1}{2}\pm3\frac{1}{2}
\\
x_{1}=6 \qquad x_{2}=-1
\end{array}\\ \end{array} \end{array}$