Geometrie-Viereck-Quadrat

$A = a^{2}$
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$a = \sqrt{A}$
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$U = 4\cdot a$
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$a = \frac{U}{4}$
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$d = a\cdot \sqrt{2}$
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$a = \frac{d}{\sqrt{2}}$
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Beispiel Nr: 07
$\begin{array}{l} \text{Gegeben:}\\\text{Seite} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Diagonale} \qquad d \qquad [m] \\ \\ d = a\cdot \sqrt{2}\\ \textbf{Gegeben:} \\ a=\frac{15}{16}m \qquad \\ \\ \textbf{Rechnung:} \\ d = a\cdot \sqrt{2} \\ a=\frac{15}{16}m\\ d = \frac{15}{16}m\cdot \sqrt{2}\\\\d=1,33m \\\\\\ \small \begin{array}{|l|} \hline a=\\ \hline \frac{15}{16} m \\ \hline 9\frac{3}{8} dm \\ \hline 93\frac{3}{4} cm \\ \hline 937\frac{1}{2} mm \\ \hline 9,38\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline d=\\ \hline 1,33 m \\ \hline 13,3 dm \\ \hline 133 cm \\ \hline 1,33\cdot 10^{3} mm \\ \hline 1,33\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$