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$ h = \frac{1}{2}\cdot g\cdot t^{2} $
$ g = \frac{2\cdot h}{ t^{2} } $
$ t = \sqrt{\frac{2\cdot h}{g}} $
$ v = \sqrt{2\cdot h\cdot g} $
$ h = \frac{ v^{2} }{2\cdot g} $
Mechanik-Kinematik-Freier Fall
$\begin{array}{l}
\text{Gegeben:}\\\text{Zeit} \qquad t \qquad [s] \\
\text{Fallbeschleunigung} \qquad g \qquad [\frac{m}{s^{2} }] \\
\\ \text{Gesucht:} \\\text{Fallhöhe} \qquad h \qquad [m] \\
\end{array}$