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$ T = 273,15 + \tau $
$ \tau = T-273,15 $
$ T_{F} = \frac{9}{5}\cdot \tau +32 $
$ \tau = \frac{5}{9}\cdot (T_{F} - 32) $
$ T_{R} = \frac{9}{5}\cdot \tau + 491,67 $
$ \tau = \frac{5}{9}\cdot (T_{R} - 491,67) $
Wärmelehre-Temperatur-Termperatur - Umrechnungen
$\begin{array}{l}
\text{Gegeben:}\\\text{Temperatur} \qquad \tau \qquad [°C] \\
\\ \text{Gesucht:} \\\text{Temperatur} \qquad T_{R} \qquad [°R] \\
\end{array}$