Geometrie-Viereck-Parallelogramm
$A = g\cdot h$
$g = \frac{A}{h}$
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$h = \frac{A}{g}$
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Beispiel Nr: 02
$\begin{array}{l}
\text{Gegeben:}\\\text{Fläche} \qquad A \qquad [m^{2}] \\
\text{Höhe} \qquad h \qquad [m] \\
\\ \text{Gesucht:} \\\text{Grundlinie} \qquad g \qquad [m] \\
\\ g = \frac{A}{h}\\ \textbf{Gegeben:} \\ A=1m^{2} \qquad h=2m \qquad \\ \\ \textbf{Rechnung:} \\
g = \frac{A}{h} \\
A=1m^{2}\\
h=2m\\
g = \frac{1m^{2}}{2m}\\\\g=\frac{1}{2}m
\\\\\\ \small \begin{array}{|l|} \hline A=\\ \hline 1 m^2 \\ \hline 100 dm^2 \\ \hline 10^{4} cm^2 \\ \hline 10^{6} mm^2 \\ \hline \frac{1}{100} a \\ \hline 0,0001 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline h=\\ \hline 2 m \\ \hline 20 dm \\ \hline 200 cm \\ \hline 2\cdot 10^{3} mm \\ \hline 2\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline g=\\ \hline \frac{1}{2} m \\ \hline 5 dm \\ \hline 50 cm \\ \hline 500 mm \\ \hline 5\cdot 10^{5} \mu m \\ \hline \end{array} \end{array}$