Geometrie-Viereck-Parallelogramm

$A = g\cdot h$
$g = \frac{A}{h}$
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$h = \frac{A}{g}$
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Beispiel Nr: 12
$\begin{array}{l} \text{Gegeben:}\\\text{Fläche} \qquad A \qquad [m^{2}] \\ \text{Höhe} \qquad h \qquad [m] \\ \\ \text{Gesucht:} \\\text{Grundlinie} \qquad g \qquad [m] \\ \\ g = \frac{A}{h}\\ \textbf{Gegeben:} \\ A=\frac{3}{5}m^{2} \qquad h=1m \qquad \\ \\ \textbf{Rechnung:} \\ g = \frac{A}{h} \\ A=\frac{3}{5}m^{2}\\ h=1m\\ g = \frac{\frac{3}{5}m^{2}}{1m}\\\\g=\frac{3}{5}m \\\\\\ \small \begin{array}{|l|} \hline A=\\ \hline \frac{3}{5} m^2 \\ \hline 60 dm^2 \\ \hline 6\cdot 10^{3} cm^2 \\ \hline 6\cdot 10^{5} mm^2 \\ \hline 0,006 a \\ \hline 6\cdot 10^{-5} ha \\ \hline \end{array} \small \begin{array}{|l|} \hline h=\\ \hline 1 m \\ \hline 10 dm \\ \hline 100 cm \\ \hline 10^{3} mm \\ \hline 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline g=\\ \hline \frac{3}{5} m \\ \hline 6 dm \\ \hline 60 cm \\ \hline 600 mm \\ \hline 6\cdot 10^{5} \mu m \\ \hline \end{array} \end{array}$