Geometrie-Stereometrie-Hohlzylinder

$V = (r_{1} ^{2} - r_{2} ^{2} )\cdot \pi \cdot h$
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$r_{1} = \sqrt{\frac{ V}{\pi \cdot h}+r_{2} ^{2} }$
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$r_{2} = \sqrt{r_{1} ^{2} - \frac{ V}{\pi \cdot h}}$
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$h = \frac{ V}{(r_{1} ^{2} - r_{2} ^{2} )\cdot \pi }$
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Beispiel Nr: 01
$\begin{array}{l} \text{Gegeben:}\\\text{Körperhöhe} \qquad h \qquad [m] \\ \text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Radius 2} \qquad r_{2} \qquad [m] \\ \text{Radius 1} \qquad r_{1} \qquad [m] \\ \\ \text{Gesucht:} \\\text{Volumen} \qquad V \qquad [m^{3}] \\ \\ V = (r_{1} ^{2} - r_{2} ^{2} )\cdot \pi \cdot h\\ \textbf{Gegeben:} \\ h=4m \qquad \pi=3\frac{16}{113} \qquad r_{2}=3m \qquad r_{1}=5m \qquad \\ \\ \textbf{Rechnung:} \\ V = (r_{1} ^{2} - r_{2} ^{2} )\cdot \pi \cdot h \\ h=4m\\ \pi=3\frac{16}{113}\\ r_{2}=3m\\ r_{1}=5m\\ V = (5m ^{2} - 3m ^{2} )\cdot 3\frac{16}{113} \cdot 4m\\\\V=201m^{3} \\\\\\ \small \begin{array}{|l|} \hline h=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline r2=\\ \hline 3 m \\ \hline 30 dm \\ \hline 300 cm \\ \hline 3\cdot 10^{3} mm \\ \hline 3\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline r1=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline \end{array}\\ \small \begin{array}{|l|} \hline V=\\ \hline 201 m^3 \\ \hline 2,01\cdot 10^{5} dm^3 \\ \hline 201061932\frac{4}{5} cm^3 \\ \hline 2,01\cdot 10^{11} mm^3 \\ \hline 2,01\cdot 10^{5} l \\ \hline 2,01\cdot 10^{3} hl \\ \hline \end{array} \end{array}$