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$ sin \alpha = \frac{a}{c} $
$ a = sin \alpha \cdot c $
$ c = \frac{ a}{sin\alpha } $
$ cos \alpha = \frac{b}{c} $
$ b = cos \alpha \cdot c $
$ c = \frac{ b}{cos \alpha } $
$ tan \alpha = \frac{a}{b} $
$ a = tan \alpha \cdot b $
$ b = \frac{ a}{tan\alpha } $
Geometrie-Trigonometrie-Rechtwinkliges Dreieck
$sin \alpha = \frac{a}{c}$
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$a = sin \alpha \cdot c$
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$c = \frac{ a}{sin\alpha }$
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$cos \alpha = \frac{b}{c}$
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$b = cos \alpha \cdot c$
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$c = \frac{ b}{cos \alpha }$
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$tan \alpha = \frac{a}{b}$
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$a = tan \alpha \cdot b$
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$b = \frac{ a}{tan\alpha }$
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Beispiel Nr: 05
$\begin{array}{l}
\text{Gegeben:}\\\text{Winkel} \qquad \alpha \qquad [^{\circ}] \\
\text{Hypotenuse} \qquad c \qquad [m] \\
\\ \text{Gesucht:} \\\text{Gegenkathete zu }\alpha \qquad a \qquad [m] \\
\\ a = sin \alpha \cdot c\\ \textbf{Gegeben:} \\ \alpha=60^{\circ} \qquad c=1\frac{1}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
a = sin \alpha \cdot c \\
\alpha=60^{\circ}\\
c=1\frac{1}{5}m\\
a = sin 60^{\circ} \cdot 1\frac{1}{5}m\\\\a=1,04m
\\\\\\ \small \begin{array}{|l|} \hline alpha=\\ \hline 60 ° \\ \hline 3,6\cdot 10^{3} \text{'} \\ \hline 2,16\cdot 10^{5} \text{''} \\ \hline 66\frac{2}{3} gon \\ \hline 1,05 rad \\ \hline \end{array} \small \begin{array}{|l|} \hline c=\\ \hline 1\frac{1}{5} m \\ \hline 12 dm \\ \hline 120 cm \\ \hline 1,2\cdot 10^{3} mm \\ \hline 1,2\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 1,04 m \\ \hline 10,4 dm \\ \hline 104 cm \\ \hline 1,04\cdot 10^{3} mm \\ \hline 1,04\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$