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$ sin \alpha = \frac{a}{c} $
$ a = sin \alpha \cdot c $
$ c = \frac{ a}{sin\alpha } $
$ cos \alpha = \frac{b}{c} $
$ b = cos \alpha \cdot c $
$ c = \frac{ b}{cos \alpha } $
$ tan \alpha = \frac{a}{b} $
$ a = tan \alpha \cdot b $
$ b = \frac{ a}{tan\alpha } $
Geometrie-Trigonometrie-Rechtwinkliges Dreieck
$sin \alpha = \frac{a}{c}$
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$a = sin \alpha \cdot c$
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$c = \frac{ a}{sin\alpha }$
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$cos \alpha = \frac{b}{c}$
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$b = cos \alpha \cdot c$
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$c = \frac{ b}{cos \alpha }$
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$tan \alpha = \frac{a}{b}$
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$a = tan \alpha \cdot b$
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$b = \frac{ a}{tan\alpha }$
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Beispiel Nr: 05
$\begin{array}{l}
\text{Gegeben:}\\\text{Hypotenuse} \qquad c \qquad [m] \\
\text{Gegenkathete zu }\alpha \qquad a \qquad [m] \\
\\ \text{Gesucht:} \\\text{Winkel} \qquad \alpha \qquad [^{\circ}] \\
\\ sin \alpha = \frac{a}{c}\\ \textbf{Gegeben:} \\ c=\frac{3}{10}m \qquad a=\frac{1}{10}m \\ \\ \textbf{Rechnung:} \\
sin \alpha = \frac{a}{c} \\
c=\frac{3}{10}m\\
a=\frac{1}{10}m\\
sin \alpha = \frac{\frac{1}{10}m}{\frac{3}{10}m}\\ \\
\alpha=19,5^{\circ}
\\\\\\ \small \begin{array}{|l|} \hline c=\\ \hline \frac{3}{10} m \\ \hline 3 dm \\ \hline 30 cm \\ \hline 300 mm \\ \hline 3\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline \frac{1}{10} m \\ \hline 1 dm \\ \hline 10 cm \\ \hline 100 mm \\ \hline 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline alpha=\\ \hline 19,5 ° \\ \hline 1,17\cdot 10^{3} \text{'} \\ \hline 7,01\cdot 10^{4} \text{''} \\ \hline 21,6 gon \\ \hline 0,34 rad \\ \hline \end{array} \end{array}$