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$ sin \alpha = \frac{a}{c} $
$ a = sin \alpha \cdot c $
$ c = \frac{ a}{sin\alpha } $
$ cos \alpha = \frac{b}{c} $
$ b = cos \alpha \cdot c $
$ c = \frac{ b}{cos \alpha } $
$ tan \alpha = \frac{a}{b} $
$ a = tan \alpha \cdot b $
$ b = \frac{ a}{tan\alpha } $
Geometrie-Trigonometrie-Rechtwinkliges Dreieck
$sin \alpha = \frac{a}{c}$
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$a = sin \alpha \cdot c$
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$c = \frac{ a}{sin\alpha }$
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$cos \alpha = \frac{b}{c}$
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$b = cos \alpha \cdot c$
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$c = \frac{ b}{cos \alpha }$
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$tan \alpha = \frac{a}{b}$
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$a = tan \alpha \cdot b$
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$b = \frac{ a}{tan\alpha }$
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Beispiel Nr: 06
$\begin{array}{l}
\text{Gegeben:}\\\text{Ankathete zu } \alpha \qquad b \qquad [m] \\
\text{Gegenkathete zu } \alpha \qquad a \qquad [m] \\
\\ \text{Gesucht:} \\\text{Winkel} \qquad \alpha \qquad [^{\circ}] \\
\\ tan \alpha = \frac{a}{b}\\ \textbf{Gegeben:} \\ b=6\frac{1}{5}m \qquad a=3\frac{4}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
tan \alpha = \frac{a}{b} \\
b=6\frac{1}{5}m\\
a=3\frac{4}{5}m\\
tan \alpha = \frac{3\frac{4}{5}m}{6\frac{1}{5}m}\\\\\alpha=31,5^{\circ}
\\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 6\frac{1}{5} m \\ \hline 62 dm \\ \hline 620 cm \\ \hline 6,2\cdot 10^{3} mm \\ \hline 6,2\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 3\frac{4}{5} m \\ \hline 38 dm \\ \hline 380 cm \\ \hline 3,8\cdot 10^{3} mm \\ \hline 3,8\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline alpha=\\ \hline 31,5 ° \\ \hline 1,89\cdot 10^{3} \text{'} \\ \hline 1,13\cdot 10^{5} \text{''} \\ \hline 35 gon \\ \hline 0,55 rad \\ \hline \end{array} \end{array}$