Geometrie-Viereck-Rechtwinkliges Trapez

$A = \frac{a+c}{ 2}\cdot h$
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$a = \frac{2\cdot A}{ h} - c$
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$c = \frac{2\cdot A}{ h} - a$
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$h = \frac{2\cdot A}{a+c}$
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Beispiel Nr: 11
$\begin{array}{l} \text{Gegeben:}\\\text{Grundlinie c} \qquad c \qquad [m] \\ \text{Grundlinie a} \qquad a \qquad [m] \\ \text{Höhe} \qquad h \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{a+c}{ 2}\cdot h\\ \textbf{Gegeben:} \\ c=\frac{1}{25}m \qquad a=4m \qquad h=5m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{a+c}{ 2}\cdot h \\ c=\frac{1}{25}m\\ a=4m\\ h=5m\\ A = \frac{4m+\frac{1}{25}m}{ 2}\cdot 5m\\\\A=10\frac{1}{10}m^{2} \\\\\\ \small \begin{array}{|l|} \hline c=\\ \hline \frac{1}{25} m \\ \hline \frac{2}{5} dm \\ \hline 4 cm \\ \hline 40 mm \\ \hline 4\cdot 10^{4} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline h=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 10\frac{1}{10} m^2 \\ \hline 1,01\cdot 10^{3} dm^2 \\ \hline 1,01\cdot 10^{5} cm^2 \\ \hline 1,01\cdot 10^{7} mm^2 \\ \hline 0,101 a \\ \hline 0,00101 ha \\ \hline \end{array} \end{array}$