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$ d= 2\cdot r $
$ r= \frac{d}{2} $
$ A = r^{2} \cdot \pi $
$ r = \sqrt{\frac{A}{\pi }} $
$ U = 2\cdot r\cdot \pi $
$ r = \frac{ U}{2\cdot \pi } $
Geometrie-Kreis-Kreis
$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 04
$\begin{array}{l}
\text{Gegeben:}\\\text{Kreiszahl} \qquad \pi \qquad [] \\
\text{Radius} \qquad r \qquad [m] \\
\\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\
\\ A = r^{2} \cdot \pi\\ \textbf{Gegeben:} \\ \pi=3\frac{16}{113} \qquad r=3\frac{1}{2}m \qquad \\ \\ \textbf{Rechnung:} \\
A = r^{2} \cdot \pi \\
\pi=3\frac{16}{113}\\
r=3\frac{1}{2}m\\
A = (3\frac{1}{2}m)^{2} \cdot 3\frac{16}{113}\\\\A=38,5m^{2}
\\\\ \small \begin{array}{|l|} \hline r=\\ \hline 3\frac{1}{2} m \\ \hline 35 dm \\ \hline 350 cm \\ \hline 3,5\cdot 10^{3} mm \\ \hline 3,5\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 38,5 m^2 \\ \hline 3,85\cdot 10^{3} dm^2 \\ \hline 3,85\cdot 10^{5} cm^2 \\ \hline 38484510\frac{23}{40} mm^2 \\ \hline 0,385 a \\ \hline 0,00385 ha \\ \hline \end{array} \end{array}$