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$ d= 2\cdot r $
$ r= \frac{d}{2} $
$ A = r^{2} \cdot \pi $
$ r = \sqrt{\frac{A}{\pi }} $
$ U = 2\cdot r\cdot \pi $
$ r = \frac{ U}{2\cdot \pi } $
Geometrie-Kreis-Kreis
$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 06
$\begin{array}{l}
\text{Gegeben:}\\\text{Durchmesser} \qquad d \qquad [m] \\
\\ \text{Gesucht:} \\\text{Radius} \qquad r \qquad [m] \\
\\ r= \frac{d}{2}\\ \textbf{Gegeben:} \\ d=\frac{1}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
r= \frac{d}{2} \\
d=\frac{1}{5}m\\
r= \frac{\frac{1}{5}m}{2}\\\\r=\frac{1}{10}m
\\\\\\ \small \begin{array}{|l|} \hline d=\\ \hline \frac{1}{5} m \\ \hline 2 dm \\ \hline 20 cm \\ \hline 200 mm \\ \hline 2\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline r=\\ \hline \frac{1}{10} m \\ \hline 1 dm \\ \hline 10 cm \\ \hline 100 mm \\ \hline 10^{5} \mu m \\ \hline \end{array} \end{array}$