Geometrie-Kreis-Kreis

$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 10
$\begin{array}{l} \text{Gegeben:}\\\text{Durchmesser} \qquad d \qquad [m] \\ \\ \text{Gesucht:} \\\text{Radius} \qquad r \qquad [m] \\ \\ r= \frac{d}{2}\\ \textbf{Gegeben:} \\ d=1\frac{2}{3}m \qquad \\ \\ \textbf{Rechnung:} \\ r= \frac{d}{2} \\ d=1\frac{2}{3}m\\ r= \frac{1\frac{2}{3}m}{2}\\\\r=\frac{5}{6}m \\\\\\ \small \begin{array}{|l|} \hline d=\\ \hline 1\frac{2}{3} m \\ \hline 16\frac{2}{3} dm \\ \hline 166\frac{2}{3} cm \\ \hline 1666\frac{2}{3} mm \\ \hline 1666666\frac{2}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline r=\\ \hline \frac{5}{6} m \\ \hline 8\frac{1}{3} dm \\ \hline 83\frac{1}{3} cm \\ \hline 833\frac{1}{3} mm \\ \hline 833333\frac{1}{3} \mu m \\ \hline \end{array} \end{array}$