Geometrie-Kreis-Kreis

$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 06
$\begin{array}{l} \text{Gegeben:}\\\text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Fläche} \qquad A \qquad [m^{2}] \\ \\ \text{Gesucht:} \\\text{Radius} \qquad r \qquad [m] \\ \\ r = \sqrt{\frac{A}{\pi }}\\ \textbf{Gegeben:} \\ \pi=23\frac{16}{113} \qquad A=35m^{2} \qquad \\ \\ \textbf{Rechnung:} \\ r = \sqrt{\frac{A}{\pi }} \\ \pi=23\frac{16}{113}\\ A=35m^{2}\\ r = \sqrt{\frac{35m^{2}}{23\frac{16}{113} }}\\\\r=1,23m \\\\ \small \begin{array}{|l|} \hline A=\\ \hline 35 m^2 \\ \hline 3,5\cdot 10^{3} dm^2 \\ \hline 3,5\cdot 10^{5} cm^2 \\ \hline 3,5\cdot 10^{7} mm^2 \\ \hline \frac{7}{20} a \\ \hline 0,0035 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline r=\\ \hline 1,23 m \\ \hline 12,3 dm \\ \hline 123 cm \\ \hline 1,23\cdot 10^{3} mm \\ \hline 1,23\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$