Geometrie-Kreis-Kreis

$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 07
$\begin{array}{l} \text{Gegeben:}\\\text{Radius} \qquad r \qquad [m] \\ \\ \text{Gesucht:} \\\text{Durchmesser} \qquad d \qquad [m] \\ \\ d= 2\cdot r\\ \textbf{Gegeben:} \\ r=\frac{7}{8}m \qquad \\ \\ \textbf{Rechnung:} \\ d= 2\cdot r \\ r=\frac{7}{8}m\\ d= 2\cdot \frac{7}{8}m\\\\d=1\frac{3}{4}m \\\\\\ \small \begin{array}{|l|} \hline r=\\ \hline \frac{7}{8} m \\ \hline 8\frac{3}{4} dm \\ \hline 87\frac{1}{2} cm \\ \hline 875 mm \\ \hline 8,75\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline d=\\ \hline 1\frac{3}{4} m \\ \hline 17\frac{1}{2} dm \\ \hline 175 cm \\ \hline 1,75\cdot 10^{3} mm \\ \hline 1,75\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$