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 $ d= 2\cdot r $
                                      
                                          $ r= \frac{d}{2} $
                                      
                                          $ A = r^{2} \cdot \pi $
                                      
                                          $ r = \sqrt{\frac{A}{\pi }} $
                                      
                                          $ U = 2\cdot r\cdot \pi $
                                      
                                          $ r = \frac{ U}{2\cdot \pi } $
Geometrie-Kreis-Kreis
 $d= 2\cdot r$ 
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 $r= \frac{d}{2}$ 
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 $A = r^{2} \cdot \pi$ 
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 $r = \sqrt{\frac{A}{\pi }}$ 
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 $U = 2\cdot r\cdot \pi$ 
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 $r = \frac{ U}{2\cdot \pi }$ 
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                Beispiel Nr: 08
            
        
           $\begin{array}{l} 
      \text{Gegeben:}\\\text{Kreiszahl} \qquad \pi \qquad [] \\
      \text{Radius} \qquad r \qquad [m] \\
      \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\
     \\ A = r^{2} \cdot \pi\\ \textbf{Gegeben:} \\ \pi=3\frac{16}{113} \qquad r=5\frac{1}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
      A = r^{2} \cdot \pi \\
      \pi=3\frac{16}{113}\\
      r=5\frac{1}{5}m\\
      A = (5\frac{1}{5}m)^{2} \cdot 3\frac{16}{113}\\\\A=84,9m^{2}
    \\\\ \small \begin{array}{|l|} \hline r=\\  \hline 5\frac{1}{5} m  \\  \hline 52 dm  \\  \hline 520 cm  \\  \hline 5,2\cdot 10^{3} mm  \\  \hline 5,2\cdot 10^{6} \mu m  \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\  \hline 84,9 m^2  \\  \hline 8,49\cdot 10^{3} dm^2  \\  \hline 8,49\cdot 10^{5} cm^2  \\  \hline 84948666\frac{76}{125} mm^2  \\  \hline 0,849 a  \\  \hline 0,00849 ha  \\ \hline \end{array}  \end{array}$