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$ A = \frac{3 \cdot a^{2} }{2}\cdot \sqrt{3} $
$ a = \sqrt{\frac{A\cdot 2}{3 \cdot \sqrt{3}}} $
$ \rho= \frac{a}{2}\cdot \sqrt{3} $
$ a = \frac{\rho \cdot 2}{\sqrt{3}} $
Geometrie-Polygone (n-Ecken)-Sechseck
$A = \frac{3 \cdot a^{2} }{2}\cdot \sqrt{3}$
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$a = \sqrt{\frac{A\cdot 2}{3 \cdot \sqrt{3}}}$
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$\rho= \frac{a}{2}\cdot \sqrt{3}$
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$a = \frac{\rho \cdot 2}{\sqrt{3}}$
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Beispiel Nr: 09
$\begin{array}{l}
\text{Gegeben:}\\\text{Inkreisradius} \qquad \rho \qquad [m] \\
\\ \text{Gesucht:} \\\text{Seite} \qquad a \qquad [m] \\
\\ a = \frac{\rho \cdot 2}{\sqrt{3}}\\ \textbf{Gegeben:} \\ \rho=1\frac{1}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
a = \frac{\rho \cdot 2}{\sqrt{3}} \\
\rho=1\frac{1}{5}m\\
a = \frac{1\frac{1}{5}m\cdot 2}{\sqrt{3}}\\\\a=1,39m
\\\\\\ \small \begin{array}{|l|} \hline rho=\\ \hline 1\frac{1}{5} m \\ \hline 12 dm \\ \hline 120 cm \\ \hline 1,2\cdot 10^{3} mm \\ \hline 1,2\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 1,39 m \\ \hline 13,9 dm \\ \hline 139 cm \\ \hline 1,39\cdot 10^{3} mm \\ \hline 1,39\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$