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$ d= 2\cdot r $
$ r= \frac{d}{2} $
$ A = r^{2} \cdot \pi $
$ r = \sqrt{\frac{A}{\pi }} $
$ U = 2\cdot r\cdot \pi $
$ r = \frac{ U}{2\cdot \pi } $
Geometrie-Kreis-Kreis
$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 17
$\begin{array}{l}
\text{Gegeben:}\\\text{Radius} \qquad r \qquad [m] \\
\\ \text{Gesucht:} \\\text{Durchmesser} \qquad d \qquad [m] \\
\\ d= 2\cdot r\\ \textbf{Gegeben:} \\ r=2\frac{1}{3}m \qquad \\ \\ \textbf{Rechnung:} \\
d= 2\cdot r \\
r=2\frac{1}{3}m\\
d= 2\cdot 2\frac{1}{3}m\\\\d=4\frac{2}{3}m
\\\\\\ \small \begin{array}{|l|} \hline r=\\ \hline 2\frac{1}{3} m \\ \hline 23\frac{1}{3} dm \\ \hline 233\frac{1}{3} cm \\ \hline 2333\frac{1}{3} mm \\ \hline 2333333\frac{1}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline d=\\ \hline 4\frac{2}{3} m \\ \hline 46\frac{2}{3} dm \\ \hline 466\frac{2}{3} cm \\ \hline 4666\frac{2}{3} mm \\ \hline 4666666\frac{2}{3} \mu m \\ \hline \end{array} \end{array}$