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$ A = \frac{1}{2}\cdot e\cdot f $
$ e = \frac{2\cdot A}{ f} $
$ f = \frac{2\cdot A}{ e} $
Geometrie-Viereck-Raute
$A = \frac{1}{2}\cdot e\cdot f$
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$e = \frac{2\cdot A}{ f}$
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$f = \frac{2\cdot A}{ e}$
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Beispiel Nr: 07
$\begin{array}{l}
\text{Gegeben:}\\\text{Fläche} \qquad A \qquad [m^{2}] \\
\text{Diagonale e} \qquad e \qquad [m] \\
\\ \text{Gesucht:} \\\text{Diagonale f} \qquad f \qquad [m] \\
\\ f = \frac{2\cdot A}{ e}\\ \textbf{Gegeben:} \\ A=1\frac{2}{3}m^{2} \qquad e=\frac{4}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
f = \frac{2\cdot A}{ e} \\
A=1\frac{2}{3}m^{2}\\
e=\frac{4}{5}m\\
f = \frac{2\cdot 1\frac{2}{3}m^{2}}{ \frac{4}{5}m}\\\\f=4\frac{1}{6}m
\\\\\\ \small \begin{array}{|l|} \hline A=\\ \hline 1\frac{2}{3} m^2 \\ \hline 166\frac{2}{3} dm^2 \\ \hline 16666\frac{2}{3} cm^2 \\ \hline 1666666\frac{2}{3} mm^2 \\ \hline \frac{1}{60} a \\ \hline 0,000167 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline e=\\ \hline \frac{4}{5} m \\ \hline 8 dm \\ \hline 80 cm \\ \hline 800 mm \\ \hline 8\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline f=\\ \hline 4\frac{1}{6} m \\ \hline 41\frac{2}{3} dm \\ \hline 416\frac{2}{3} cm \\ \hline 4166\frac{2}{3} mm \\ \hline 4166666\frac{2}{3} \mu m \\ \hline \end{array} \end{array}$