Geometrie-Viereck-Raute

$A = \frac{1}{2}\cdot e\cdot f$
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$e = \frac{2\cdot A}{ f}$
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$f = \frac{2\cdot A}{ e}$
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Beispiel Nr: 04
$\begin{array}{l} \text{Gegeben:}\\\text{Diagonale f} \qquad f \qquad [m] \\ \text{Diagonale e} \qquad e \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{1}{2}\cdot e\cdot f\\ \textbf{Gegeben:} \\ f=12m \qquad e=14m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{1}{2}\cdot e\cdot f \\ f=12m\\ e=14m\\ A = \frac{1}{2}\cdot 14m\cdot 12m \\\\ A=84m^{2} \\\\\\ \small \begin{array}{|l|} \hline f=\\ \hline 12 m \\ \hline 120 dm \\ \hline 1,2\cdot 10^{3} cm \\ \hline 1,2\cdot 10^{4} mm \\ \hline 1,2\cdot 10^{7} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline e=\\ \hline 14 m \\ \hline 140 dm \\ \hline 1,4\cdot 10^{3} cm \\ \hline 1,4\cdot 10^{4} mm \\ \hline 1,4\cdot 10^{7} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 84 m^2 \\ \hline 8,4\cdot 10^{3} dm^2 \\ \hline 8,4\cdot 10^{5} cm^2 \\ \hline 8,4\cdot 10^{7} mm^2 \\ \hline \frac{21}{25} a \\ \hline 0,0084 ha \\ \hline \end{array} \end{array}$