Geometrie-Viereck-Raute

$A = \frac{1}{2}\cdot e\cdot f$
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$e = \frac{2\cdot A}{ f}$
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$f = \frac{2\cdot A}{ e}$
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Beispiel Nr: 01
$\begin{array}{l} \text{Gegeben:}\\\text{Diagonale f} \qquad f \qquad [m] \\ \text{Diagonale e} \qquad e \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{1}{2}\cdot e\cdot f\\ \textbf{Gegeben:} \\ f=5m \qquad e=3m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{1}{2}\cdot e\cdot f \\ f=5m\\ e=3m\\ A = \frac{1}{2}\cdot 3m\cdot 5m \\\\ A=7\frac{1}{2}m^{2} \\\\\\ \small \begin{array}{|l|} \hline f=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline e=\\ \hline 3 m \\ \hline 30 dm \\ \hline 300 cm \\ \hline 3\cdot 10^{3} mm \\ \hline 3\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 7\frac{1}{2} m^2 \\ \hline 750 dm^2 \\ \hline 7,5\cdot 10^{4} cm^2 \\ \hline 7,5\cdot 10^{6} mm^2 \\ \hline \frac{3}{40} a \\ \hline 0,00075 ha \\ \hline \end{array} \end{array}$