Geometrie-Viereck-Raute



Beispiel Nr: 07
$ \text{Gegeben:}\\\text{Diagonale f} \qquad f \qquad [m] \\ \text{Diagonale e} \qquad e \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{1}{2}\cdot e\cdot f\\ \textbf{Gegeben:} \\ f=1\frac{2}{3}m \qquad e=\frac{4}{5}m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{1}{2}\cdot e\cdot f \\ f=1\frac{2}{3}m\\ e=\frac{4}{5}m\\ A = \frac{1}{2}\cdot \frac{4}{5}m\cdot 1\frac{2}{3}m \\\\ A=\frac{2}{3}m^{2} \\\\\\ \small \begin{array}{|l|} \hline f=\\ \hline 1\frac{2}{3} m \\ \hline 16\frac{2}{3} dm \\ \hline 166\frac{2}{3} cm \\ \hline 1666\frac{2}{3} mm \\ \hline 1666666\frac{2}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline e=\\ \hline \frac{4}{5} m \\ \hline 8 dm \\ \hline 80 cm \\ \hline 800 mm \\ \hline 8\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline \frac{2}{3} m^2 \\ \hline 66\frac{2}{3} dm^2 \\ \hline 6666\frac{2}{3} cm^2 \\ \hline 666666\frac{2}{3} mm^2 \\ \hline 0,00667 a \\ \hline 6,67\cdot 10^{-5} ha \\ \hline \end{array}$