Geometrie-Viereck-Raute

$A = \frac{1}{2}\cdot e\cdot f$
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$e = \frac{2\cdot A}{ f}$
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$f = \frac{2\cdot A}{ e}$
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Beispiel Nr: 12
$\begin{array}{l} \text{Gegeben:}\\\text{Diagonale f} \qquad f \qquad [m] \\ \text{Diagonale e} \qquad e \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{1}{2}\cdot e\cdot f\\ \textbf{Gegeben:} \\ f=\frac{3}{5}m \qquad e=1m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{1}{2}\cdot e\cdot f \\ f=\frac{3}{5}m\\ e=1m\\ A = \frac{1}{2}\cdot 1m\cdot \frac{3}{5}m \\\\ A=\frac{3}{10}m^{2} \\\\\\ \small \begin{array}{|l|} \hline f=\\ \hline \frac{3}{5} m \\ \hline 6 dm \\ \hline 60 cm \\ \hline 600 mm \\ \hline 6\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline e=\\ \hline 1 m \\ \hline 10 dm \\ \hline 100 cm \\ \hline 10^{3} mm \\ \hline 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline \frac{3}{10} m^2 \\ \hline 30 dm^2 \\ \hline 3\cdot 10^{3} cm^2 \\ \hline 3\cdot 10^{5} mm^2 \\ \hline 0,003 a \\ \hline 3\cdot 10^{-5} ha \\ \hline \end{array} \end{array}$